Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 87: 91


$5\left( 7a+11c+1 \right)$

Work Step by Step

The $GCF$ of the given expression, $ 35a+55c+5 ,$ is $5,$ since it is the highest number that can evenly divide (no remainder) all the terms. Factoring the $GCF$ results to \begin{array}{l}\require{cancel} 5\left( \dfrac{35a}{5}+\dfrac{55c}{5}+\dfrac{5}{5} \right) \\\\= 5\left( 7a+11c+1 \right) .\end{array}
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