## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$t=9$
Using properties of equality, the solution to the given equation, $-\dfrac{4}{3}t=-12$, is \begin{array}{l}\require{cancel} -\dfrac{3}{4}\left(-\dfrac{4}{3}t\right)=-12\left(-\dfrac{3}{4}\right) \\\\ \dfrac{12}{12}t=-3\cdot\cancel{4}\left(-\dfrac{3}{\cancel{4}}\right) \\\\ t=9 .\end{array}