Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 87: 62



Work Step by Step

Multiplying both sides by $ -3 $, then the solution to the given equation, $ \dfrac{2}{7}=\dfrac{x}{-3} $, is \begin{array}{l}\require{cancel} -3\cdot\dfrac{2}{7}=\dfrac{x}{-3}\cdot(-3) \\\\ \dfrac{-6}{7}=\dfrac{-3x}{-3} \\\\ -\dfrac{6}{7}=x \\\\ x=-\dfrac{6}{7} .\end{array}
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