## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set: 101

#### Answer

$9,000$

#### Work Step by Step

Using the properties of equality, the value of $t$ in the given equation, $t-3590=1820$, is \begin{array}{l} t-3590+3590=1820+3590 \\\\ t=5410 .\end{array} Hence, $t+3590$ evaluates to \begin{array}{l} 5410+3590 \\\\= 9,000 .\end{array}

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