Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 87: 63



Work Step by Step

Multiplying both sides by $ -\dfrac{5}{3} $, then the solution to the given equation, $ -\dfrac{3}{5}r=-\dfrac{3}{5} $, is \begin{array}{l}\require{cancel} \left(-\dfrac{5}{3}\right)\left(-\dfrac{3}{5}r\right)=\left(-\dfrac{3}{5}\right)\left(-\dfrac{5}{3}\right) \\\\ \dfrac{15}{15}r=\dfrac{15}{15} \\\\ r=1 .\end{array}
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