## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$r=1$
Multiplying both sides by $-\dfrac{5}{3}$, then the solution to the given equation, $-\dfrac{3}{5}r=-\dfrac{3}{5}$, is \begin{array}{l}\require{cancel} \left(-\dfrac{5}{3}\right)\left(-\dfrac{3}{5}r\right)=\left(-\dfrac{3}{5}\right)\left(-\dfrac{5}{3}\right) \\\\ \dfrac{15}{15}r=\dfrac{15}{15} \\\\ r=1 .\end{array}