Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.3 Studying Solutions of Quadratic Equations - 11.3 Exercise Set - Page 718: 59

Answer

$$3\sqrt{30}b^6a^{\frac{7}{2}}$$

Work Step by Step

Using the rules of radicals to simplify, we find: $$ \sqrt{270}\sqrt{a^7}\sqrt{b^{12}}\\ 3\sqrt{30}b^6a^{\frac{7}{2}}$$
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