## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

To determine the number and type of solutions, we use the discriminant: $$y^2-4y+\frac{9}{4}=0 \\ \sqrt{\left(-16\right)^2-4\cdot \:4\cdot \:9} \\ \sqrt 7$$ Thus, we see that there will be two real solutions.