# Chapter 11 - Quadratic Functions and Equations - 11.3 Studying Solutions of Quadratic Equations - 11.3 Exercise Set - Page 718: 28

Two imaginary solutions.

#### Work Step by Step

To determine the number and type of solutions, we use the discriminant: $$x^2=\frac{1}{2}x-\frac{3}{5}\\ 10x^2-5x+6=0\\ \sqrt{\left(-5\right)^2-4\cdot \:10\cdot \:6} \\ \sqrt{-215}$$ Since the discriminant is negative, we see that there will be two imaginary solutions.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.