Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.3 Studying Solutions of Quadratic Equations - 11.3 Exercise Set - Page 718: 28


Two imaginary solutions.

Work Step by Step

To determine the number and type of solutions, we use the discriminant: $$ x^2=\frac{1}{2}x-\frac{3}{5}\\ 10x^2-5x+6=0\\ \sqrt{\left(-5\right)^2-4\cdot \:10\cdot \:6} \\ \sqrt{-215}$$ Since the discriminant is negative, we see that there will be two imaginary solutions.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.