#### Answer

Two imaginary solutions.

#### Work Step by Step

To determine the number and type of solutions, we use the discriminant:
$$ x^2=\frac{1}{2}x-\frac{3}{5}\\ 10x^2-5x+6=0\\ \sqrt{\left(-5\right)^2-4\cdot \:10\cdot \:6} \\ \sqrt{-215}$$
Since the discriminant is negative, we see that there will be two imaginary solutions.