Answer
$3x^{2}-14x+8=0$
Work Step by Step
$x=4$ or $ x=\displaystyle \frac{2}{3}\qquad$....get $0$'s on one side.
$x-4=0$ or $ x-\displaystyle \frac{2}{3}=0\qquad$....Use the principle of zero products (multiplying). The solutions of this equation are $4$ and $\displaystyle \frac{2}{3}$.
$(x-4)(x-\displaystyle \frac{2}{3})=0\qquad$...use the FOIL method to multiply.
$ x^{2}-\displaystyle \frac{2}{3}x-4x+\frac{8}{3}=0\qquad$...combine like terms.
$ x^{2}-\displaystyle \frac{14}{3}x+\frac{8}{3}=0\qquad$...multiply both sides by $3$ to clear fractions.
$3x^{2}-14x+8=0$
