Answer
$4x^{2}-23x+15=0$
Work Step by Step
$x=5$ or $ x=\displaystyle \frac{3}{4}\qquad$....get $0$'s on one side.
$x-5=0$ or $ x-\displaystyle \frac{3}{4}=0\qquad$....Use the principle of zero products (multiplying). The solutions of this equation are $5$ and $\displaystyle \frac{3}{4}$.
$(x-5)(x-\displaystyle \frac{3}{4})=0\qquad$...use the FOIL method to multiply.
$ x^{2}-\displaystyle \frac{3}{4}x-5x+\frac{15}{4}=0\qquad$...combine like terms.
$ x^{2}-\displaystyle \frac{23}{4}x+\frac{15}{4}=0\qquad$...multiply both sides by $4$ to clear fractions.
$4x^{2}-23x+15=0$
