Chapter 11 - Quadratic Functions and Equations - 11.3 Studying Solutions of Quadratic Equations - 11.3 Exercise Set - Page 718: 54

$$x^3+3x^2-10x=0 $$

To write a cubic equation with the given values as solutions, we find the corresponding factors. We then FOIL out the factors to find the original quadratic equation: $$ 0=-\left(x+5\right)\left(x\right)\left(x-2\right) \\ 0=\left(x\right)\left(x^2+3x-10\right) \\ 0=x^3+3x^2-10x $$