Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.3 Studying Solutions of Quadratic Equations - 11.3 Exercise Set - Page 718: 26


There are two rational solutions.

Work Step by Step

$ 5x^{2}=48x\qquad$....add $-48x$ to each side to write in form of $ax^{2}+bx+c=0$. $ 5x^{2}-48x=0\qquad$.... $a=5,\ b=-48,\ c=0$ $ b^{2}-4ac\qquad$....substitute $b$ for $-48,\ a$ for $5$ and $c$ for $0$ $=(-48)^{2}-4\cdot 5\cdot(0)$ $=2304-0$ $=2304$ Since the discriminant is a positive number that is a perfect square $(48^{2})$, there are two rational solutions.
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