## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$4x^{2}-12x+9=0\qquad$.... $a=4,\ b=-12,\ c=9$ $b^{2}-4ac\qquad$....substitute $b$ for $-12,\ a$ for $4$ and $c$ for $9$ $=(-12)^{2}-4\cdot 4\cdot 9$ $=144-144$ $=0$ Since the discriminant equals $0$, there is one repeated rational solution.