Answer
$$0=x^2-3$$
Work Step by Step
To write a quadratic equation with the given values as solutions, we find the corresponding factors. We then FOIL out the factors to find the original quadratic equation:
$$ \left(x+\sqrt{3}\right)\left(x-\sqrt{3}\right)=0 \\ x^2-\left(\sqrt{3}\right)^2 =0 \\ 0=x^2-3$$