Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.3 Studying Solutions of Quadratic Equations - 11.3 Exercise Set - Page 718: 41

Answer

$$0=x^2-3$$

Work Step by Step

To write a quadratic equation with the given values as solutions, we find the corresponding factors. We then FOIL out the factors to find the original quadratic equation: $$ \left(x+\sqrt{3}\right)\left(x-\sqrt{3}\right)=0 \\ x^2-\left(\sqrt{3}\right)^2 =0 \\ 0=x^2-3$$
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