## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$x^{2}+4x+3=0$
$x=-1$ or $x=-3\qquad$....get $0$'s on one side. $x+1=0$ or $x+3=0\qquad$....Use the principle of zero products (multiplying). The solutions of this equation are $-1$ and $-3$. $(x+1)(x+3)=0\qquad$...use the FOIL method to multiply. $x^{2}+3x+x+3=0\qquad$...combine like terms. $x^{2}+4x+3=0$