## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$x^{2}-6x+9=0$
$x=3\qquad$...add $-3$ to both sides. $x-3=0\qquad$....square both sides. $(x-3)^{2}=0\qquad$....simplify using the perfect square formula $(A\pm B)^{2}=A^{2}\pm 2AB+B^{2}$ $x^{2}-6x+9=0$