Answer
$x^{2}-6x+9=0$
Work Step by Step
$ x=3\qquad$...add $-3$ to both sides.
$ x-3=0\qquad$....square both sides.
$(x-3)^{2}=0\qquad$....simplify using the perfect square formula $(A\pm B)^{2}=A^{2}\pm 2AB+B^{2}$
$x^{2}-6x+9=0$
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