Answer
4$a^{3}$b - 6$a^{2}$ + 8a
Work Step by Step
$\frac{-24a^{4}b^{2} + 36a^{3}b - 48a^{2}b}{-6ab}$ =
RECALL:
$\frac{b^{n}}{b^{m}}$ = $b^{n-m}$
So, $\frac{-24a^{4}b^{2} + 36a^{3}b - 48a^{2}b}{-6ab}$ = $\frac{-24a^{4}b^{2}}{-6ab}$ + $\frac{36a^{3}b}{-6ab}$ + $\frac{-48a^{2}b}{-6ab}$ =
$\frac{-24}{-6}$$a^{4-1}$$b^{2-1}$ + $\frac{36}{-6}$$a^{3-1}$$b^{1-1}$ + $\frac{-48}{-6}$$a^{2-1}$$b^{1-1}$ =
4$a^{3}$b - 6$a^{2}$ + 8a
