Answer
$4ab^2$
Work Step by Step
RECALL:
(i) $\dfrac{a^m}{a^n} = a^{m-n}$
(ii) $a^0=1, a\ne0$
Divide the coefficients, and then use the rule(s) above to obtain:
$=4a^{3-2}b^{2}c^{1-1}
\\=4a^1b^2c^0
\\=4ab^2(1)
\\=4ab^2$
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