Answer
-15$x^{2}$ + 27x$y^{3}$
Work Step by Step
$\frac{-15x^{3}y + 27x^{2}y^{4}}{xy}$ =
RECALL:
$\frac{b^{n}}{b^{m}}$ = $b^{n-m}$
So, $\frac{-15x^{3}y + 27x^{2}y^{4}}{xy}$ = $\frac{-15x^{3}y}{xy}$ + $\frac{27x^{2}y^{4}}{xy}$ =
-15$x^{3-1}$$y^{1-1}$ + 27$x^{2-1}$$y^{4-1}$ =
-15$x^{2}$ + 27x$y^{3}$
