## Elementary Algebra

-15$x^{2}$ + 27x$y^{3}$
$\frac{-15x^{3}y + 27x^{2}y^{4}}{xy}$ = RECALL: $\frac{b^{n}}{b^{m}}$ = $b^{n-m}$ So, $\frac{-15x^{3}y + 27x^{2}y^{4}}{xy}$ = $\frac{-15x^{3}y}{xy}$ + $\frac{27x^{2}y^{4}}{xy}$ = -15$x^{3-1}$$y^{1-1} + 27x^{2-1}$$y^{4-1}$ = -15$x^{2}$ + 27x$y^{3}$