Answer
$7ab^2$
Work Step by Step
RECALL:
(i) $\dfrac{a^m}{a^n} = a^{m-n}$
(ii) $a^0=1, a\ne0$
Divide the coefficients, and then use the rule(s) above to obtain:
$=7a^{4-3}b^{6-4}
\\=7a^{1}b^2
\\=7ab^2$
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