Answer
$15x^2z^4$
Work Step by Step
RECALL:
(i) $\dfrac{a^m}{a^n} = a^{m-n}$
(ii) $a^0=1, a\ne0$
Divide the coefficients, and then use the rules above to obtain:
$=15x^{3-1}y^{2-2}z^{8-4}
\\=15x^2y^0z^4
\\=15x^2(1)z^4
\\=15x^2z^4$