Answer
$4n^5-8n^2+13
$
Work Step by Step
Recall the following rule: $\frac{a^{m}}{a^{n}}=a^{m-n}$
In order to solve this problem, use the rule above and cancel out common factors that are in both the numerator and the denominator of the fraction.
$=\dfrac{-24n^8}{-6n^3} + \dfrac{48n^5}{-6n^3}- \dfrac{78n^3}{-6n^3}
\\=4n^{8-3}- 8n^{5-3}+13n^{3-3}
\\=4n^5-8n^2+13n^0
\\=4n^5-8n^2+13(1)
\\=4n^5-8n^2+13
$
