Answer
$6a^{4}b^2$
Work Step by Step
RECALL:
(i) $\dfrac{a^m}{a^n} = a^{m-n}$
(ii) $a^0=1, a\ne0$
Divide the coefficients, and then use the rule(s) above to obtain:
$=6a^{5-1}b^{4-2}
\\=6a^{4}b^2$
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