Answer
-4$a^{2}$ - 6a$b^{2}$$c^{4}$
Work Step by Step
$\frac{48a^{3}b^{2}c + 72a^{2}b^{4}c^{5}}{-12ab^{2}c}$ =
RECALL:
$\frac{b^{n}}{b^{m}}$ = $b^{n-m}$
So, $\frac{48a^{3}b^{2}c + 72a^{2}b^{4}c^{5}}{-12ab^{2}c}$ = $\frac{48a^{3}b^{2}c}{-12ab^{2}c}$ + $\frac{72a^{2}b^{4}c^{5}}{-12ab^{2}c}$ =
$\frac{48}{-12}$$a^{3-1}$$b^{2-2}c^{1-1}$ + $\frac{72}{-12}$$a^{2-1}$$b^{4-2}$$c^{5-1}$ =
-4$a^{2}$ - 6a$b^{2}$$c^{4}$
