Answer
-3$x^{4}$ - 5$x^{2}$ + 6
Work Step by Step
$\frac{-48x^{8} - 80x^{6} + 96x^{4}}{16x^{4}}$ =
RECALL:
$\frac{b^{n}}{b^{m}}$ = $b^{n-m}$
So, $\frac{-48x^{8} - 80x^{6} + 96x^{4}}{16x^{4}}$ = $\frac{-48x^{8}}{16x^{4}}$ + $\frac{-80x^{6}}{16x^{4}}$ + $\frac{96x^{4}}{16x^{4}}$ =
$\frac{-48}{16}$$x^{8-4}$ + $\frac{-80}{16}$$x^{6-4}$ + $\frac{96}{16}$$x^{4-4}$ =
-3$x^{4}$ - 5$x^{2}$ + 6