Answer
-3bc + 13$b^{2}$$c^{4}$
Work Step by Step
$\frac{12a^{2}b^{2}c^{2} - 52a^{2}b^{3}c^{5}}{-4a^{2}bc}$ =
RECALL:
$\frac{b^{n}}{b^{m}}$ = $b^{n-m}$
So, $\frac{12a^{2}b^{2}c^{2} - 52a^{2}b^{3}c^{5}}{-4a^{2}bc}$ = $\frac{12a^{2}b^{2}c^{2}}{-4a^{2}bc}$ - $\frac{52a^{2}b^{3}c^{5}}{-4a^{2}bc}$ =
$\frac{12}{-4}$$a^{2-2}$$b^{2-1}$$c^{2-1}$ - $\frac{52}{-4}$$a^{2-2}$$b^{3-1}$$c^{5-1}$ =
-3bc + 13$b^{2}$$c^{4}$
