Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4 - Page 76: 96

Answer

$= -\frac{73}{18}$

Work Step by Step

We plug in $x =- \frac{2}{3}$ and $y= \frac{3}{2}$ to obtain: $= x^{2} - 2y^{2}$ $= (-\frac{2}{3})^{2} - 2(\frac{3}{2})^{2}$ $= (\frac{4}{9}) - 2(\frac{9}{4})$ $= (\frac{4}{9}) - (\frac{18}{4})\\\\=\frac{16}{36}-\frac{162}{36}$ $= -\frac{73}{18}$
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