Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4: 104

Answer

$= 102$

Work Step by Step

We plug in $a =-3 $ and $b =-5 $ to obtain: $-a^{3} + 3b^{2}$ $= -(-3)^{3} + 3(-5)^{2}$ $= -(-27) + 3(25)$ $= 27 + 75$ $= 102$
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