Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4: 85

Answer

$= \frac{13}{12x^{2}}$

Work Step by Step

1) Multiply a fraction with the other denominator to obtain a common denominator between the two fractions. In this case, we multiply the first fraction by $3/3$ and the second fraction by $4/4$ to obtain a common denominator of $12x^{2}$ 2) Add the fractions $= \frac{-5}{4x^{2}} + \frac{7}{3x^{2}}$ $= \frac{-5(3)}{12x^{2}} + \frac{7(4)}{12x^{2}}$ $= \frac{-15 + 28}{12x^{2}}$ $= \frac{13}{12x^{2}}$
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