Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4 - Page 76: 72


$= -\frac{2a^{2}}{11b^{2}c}$

Work Step by Step

Simplify $\frac{4}{-22}$: $= -\frac{4}{22}$ $= -\frac{2}{11}$ Cancel out common factors from the numerator and the denominator: $=\frac{a^{2}c^{3}}{b^{2}c^{4}}$ We cannot cancel $a$'s and $b$'s out as both variables must be present in both the numerator and the denominator, but we can cancel out the $c$'s: $= \frac{a^{2}c^{3}}{b^{2}c^{4}}$ $= \frac{a^{2}}{b^{2}c}$ We multiply the components together to obtain: $ -\frac{2a^{2}}{11b^{2}c}$
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