# Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4 - Page 76: 73

$= \frac{x^{2}y^{2}}{4}$

#### Work Step by Step

Simplify $\frac{-5}{-20}$: $= \frac{5}{20}$ $= \frac{1}{4}$ Simplify $\frac{x^{4}y^{3}}{x^{2}y}$ 1) Cancel $x^{2}$ from the denominator and numerator, leaving you with $x^{2}$ left in the numerator and $1$ in the denominator 2) Cancel $y$ from the denominator and numerator, leaving you with $y^{2}$ in the numerator and $1$ in the denominator $= \frac{x^{2}y^{3}}{(1)y}$ $= \frac{x^{2}y^{2}}{(1)(1)}$ $= \frac{x^{2}y^{2}}{1}$ $= x^{2}y^{2}$ Multiply both components to obtain the answer: $= \frac{1}{4}( x^{2}y^{2})$ $= \frac{x^{2}y^{2}}{4}$

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