Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4: 105

Answer

$= 0.45$

Work Step by Step

We plug $x = 0.4$ and $y = -0.3$ into the expression to obtain: $y^{2} -3xy$ $= (-0.3)^{2} -3(0.4)(-0.3)$ $= 0.09 - 1.2(-0.3)$ $= 0.09 + 0.36$ $= 0.45$
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