## Elementary Algebra

$= \frac{7ab}{12}$
Recall, $\frac{a}{b} \div \frac{c}{d}=\frac{a}{b} \times \frac{d}{c}$. Thus, we simplify: $= (\frac{13ab^{2}}{12c}) \div (\frac{26b}{14c})$ $= (\frac{13ab^{2}}{12c}) \times (\frac{14c}{26b})$ In order to solve, first multiply the numerators by each other and the denominators by each other. Then, cancel out common factors in the numerator and the denominator of the fraction to obtain: $= \frac{182ab^{2}c}{312bc}$ $= \frac{7ab}{12}$