Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4: 90

Answer

$= \frac{8- 15x^{2}}{12x^{3}}$

Work Step by Step

1) Multiply a fraction with the other denominator to obtain a common denominator between the two fractions. In this case, we multiply the first fraction by $4/4$ and the second fraction by $3x^{2}/3x^{2}$ to obtain a common denominator of $12x^{3}$ 2) Subtract $= \frac{2}{3x^{3}} - \frac{5}{4x}$ $= \frac{2(4)}{12x^{3}} - \frac{5(3x^{2})}{12x^{3}}$ $= \frac{8- 15x^{2}}{12x^{3}}$
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