Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4 - Page 76: 89


$= \frac{3-8x}{6x^{3}}$

Work Step by Step

1) Multiply a fraction with the other denominator to obtain a common denominator between the two fractions. In this case, we multiply the first fraction by $3/3$ and the second fraction by $2x/2x$ to obtain a common denominator of $6x^{3}$ 2) Subtract $= \frac{1}{2x^{3}} - \frac{4}{3x^{2}}$ $= \frac{1(3)}{6x^{3}} - \frac{4(2x)}{6x^{3}}$ $= \frac{3-8x}{6x^{3}}$
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