Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4: 95

Answer

$= \frac{23}{36}$

Work Step by Step

We plug in $x = \frac{1}{2}$ and $y= -\frac{1}{3}$ to obtain: $= 3x^{2} - y^{2}$ $= 3(\frac{1}{2})^{2} - (-\frac{1}{3})^{2}$ $= 3(\frac{1}{4}) -\frac{1}{9}$ $= \frac{3}{4} - \frac{1}{9} $ $=\frac{27}{36} - \frac{4}{36}$ $= \frac{23}{36}$
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