## College Algebra 7th Edition

The solutions are $x=\left\{-1, 1\right\}$.
Use the property $a^m = a^n \longrightarrow m=n$ to obtain: $\begin{array}{ccc} &x^2-1&=&1-x^2 \\&x^2-1+x^2&=&1-x^2+x^2 \\&2x^2-1&=&1 \\&2x^2-1+1&=&1+1 \\&2x^2&=&2 \\&\dfrac{2x^2}{2} &= &\dfrac{2}{2} \\&x^2&=&1 \\&\sqrt{x^2}&=&\pm\sqrt{1} \\&x&=&\pm1 \end{array}$ Thus, the solutions are $x=\left\{-1, 1\right\}$.