College Algebra 7th Edition

$x=4$ or $x=2$
$2\log x=\log 2+\log(3x-4)$ $\log(x^{2})=\log(2(3x-4))$ $\log(x^{2})=\log(6x-8)$ $x^{2}=6x-8$ $x^{2}-6x+8=0$ $(x-4)(x-2)=0$ $(x-4)=0$ or $(x-2)=0$ $x=4$ or $x=2$