College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 51


$x=4$ or $x=2$

Work Step by Step

$2\log x=\log 2+\log(3x-4)$ $\log(x^{2})=\log(2(3x-4))$ $\log(x^{2})=\log(6x-8)$ $x^{2}=6x-8$ $x^{2}-6x+8=0$ $(x-4)(x-2)=0$ $(x-4)=0$ or $(x-2)=0$ $x=4$ or $x=2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.