College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises: 52

Answer

$x=1$

Work Step by Step

$\ln(x-\frac{1}{2})+\ln 2=2\ln x$ $\ln((x-\frac{1}{2})*2)=\ln x^{2}$ $2x-1=x^{2}$ $x^{2}-2x+1=0$ $(x-1)^{2}=0$ $x-1=0$ $x=1$
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