College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 76

Answer

$x=\left\{-0.89, 0.71\right\}$

Work Step by Step

To solve the given equation graphically, you have to treat each side of the equation as a function. Thus, using a graphing utility, graph the functions: $y=e^{x^2}-2$ (blue graph) $y=x^3-x$ (the red graph) (refer to the image below for the graph. The point/s where the graphs intersect are the points where $e^{x^2}-2=x^3-x$. The x-coordinates of these point are the solutions to the given equation. Note that the graphs intersect at the points $(-0.886, 0.191)$ and $(0.706, -0.354)$. The x-coordinates of these points are $-0.886$ and $0.706$. Rounded-off to two decimal places, the solution to the given equation is: $x=\left\{-0.89, 0.71\right\}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.