## College Algebra 7th Edition

(a) $x=\ln(\frac{10}{3})$ (b) $x\approx 1.203973$
(a) We need to solve: $3e^{x}=10$ $e^{x}=\frac{10}{3}$ We take $\ln$ of both sides to simplify: $x=\ln(\frac{10}{3})$ (b) We solve using a calculator: $x\approx 1.203973$