## College Algebra 7th Edition

The solution is $x=\dfrac{6}{5}$.
Use the property $a^m = a^n \longrightarrow m=n$ to obtain: $\begin{array}{ccc} &1-2x&=&3x-5 \\&1-2x+2x&=&3x-5+2x \\&1&=&5x-5 \\&1+5&=&5x-5+5 \\&6&=&5x \\&\dfrac{6}{5} &= &\dfrac{5x}{5} \\&\dfrac{6}{5}&=&x \end{array}$ Thus, the solution is $x=\dfrac{6}{5}$.