College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 38


(a) $x=-\ln 4$ (b) $x\approx -1.386294$

Work Step by Step

(a) We need to solve: $\frac{10}{1+e^{-x}}=2$ $10=2(1+e^{-x})$ $10=2+2e^{-x}$ $10-2=8=2e^{-x}$ $4=e^{-x}$ We take the natural log of both sides and use log rules to simplify: $\ln 4=\ln e^{-x}$ $\ln 4=-x$ $x=-\ln 4$ (b) We solve using a calculator: $x\approx -1.386294$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.