## College Algebra 7th Edition

(a) $\log3 (x-2)=\log x$ (b) $3(x-2)=x$ (c) $x=3$
(a) First, we combine the logarithms on the LHS to get the equivalent equation ___$\log3 (x-2)=\log x$___. (b) Next, we use the fact that log is one-to-one to get the equivalent equation ___$3(x-2)=x$___. (c) Now we find ___$x=3$___.