College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 68



Work Step by Step

$\log_{3}(x+15)-\log_{3}(x-1)=2$ $\log_{3}\frac{x+15}{x-1}=2$ $3^2=\frac{x+15}{x-1}$ $\frac{x+15}{x-1}=9$ $x+15=9(x-1)$ $x+15=9x-9$ $8x=24$ $x=3$
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