College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.5 - Exponential and Logarithmic Functions - 4.5 Exercises - Page 404: 67



Work Step by Step

$\log_{5}(x+1)-\log_{5}(x-1)=2$ $\log_{5}(\frac{x+1}{x-1})=2$ $5^2=\frac{x+1}{x-1}$ $25(x-1)=x+1$ $25x-25=x+1$ $24x=26$ $x=\frac{26}{24}=\frac{13}{12}$
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