College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.4 - Page 639: 36


$\left\{\begin{array}{l} -x+z=-4\\ -y=2\\ y+z=4 \end{array}\right.$

Work Step by Step

The product on the LHS is between a $3\times\underline{3}$ and a $\underline{3}\times$1 matrix, resulting in a $3\times 1$ matrix: $\left[\begin{array}{l} -1x+0y+1z\\ 0x-1y+0z\\ 0x+1y+1z \end{array}\right]=\left[\begin{array}{l} -x+z\\ -y\\ y+z \end{array}\right]$ Equating matrices, (equating corresponding elements), we have the system $\left\{\begin{array}{l} -x+z=-4\\ -y=2\\ y+z=4 \end{array}\right.$
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