College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.4 - Page 639: 21

Answer

$\begin{bmatrix}1&0&0&|&1&1&2\\0&1&0&|&1&1&1\\0&0&1&|&2&3&4\end{bmatrix}$

Work Step by Step

We are given the matrix: $A=\begin{bmatrix}1&2&-1\\-2&0&1\\1&-1&0\end{bmatrix}$ We start with the matrix: $\begin{bmatrix}1&2&-1&|&1&0&0\\-2&0&1&|&0&1&0\\1&-1&0&|&0&0&1\end{bmatrix}$ Add $2R_1$ to $R_2$: $\begin{bmatrix}1&2&-1&|&1&0&0\\0&4&-1&|&2&1&0\\1&-1&0&|&0&0&1\end{bmatrix}$ Add $-R_1$ to $R_3$: $\begin{bmatrix}1&2&-1&|&1&0&0\\0&4&-1&|&2&1&0\\0&-3&1&|&-1&0&1\end{bmatrix}$ Multiply $R_2$ by 0.25: $\begin{bmatrix}1&2&-1&|&1&0&0\\0&1&-0.25&|&0.5&0.25&0\\0&-3&1&|&-1&0&1\end{bmatrix}$ Add $-2R_2$ to $R_1$: $\begin{bmatrix}1&0&-0.5&|&0&-0.5&0\\0&1&-0.25&|&0.5&0.25&0\\0&-3&1&|&-1&0&1\end{bmatrix}$ Add $3R_2$ to $R_3$: $\begin{bmatrix}1&0&-0.5&|&0&-0.5&0\\0&1&-0.25&|&0.5&0.25&0\\0&0&0.25&|&0.5&0.75&1\end{bmatrix}$ Multiply $R_3$ by 4: $\begin{bmatrix}1&0&-0.5&|&0&-0.5&0\\0&1&-0.25&|&0.5&0.25&0\\0&0&1&|&2&3&4\end{bmatrix}$ Add $0.5R_3$ to $R_1$: $\begin{bmatrix}1&0&0&|&1&1&2\\0&1&-0.25&|&0.5&0.25&0\\0&0&1&|&2&3&4\end{bmatrix}$ Add $0.25R_3$ to $R_2$: $\begin{bmatrix}1&0&0&|&1&1&2\\0&1&0&|&1&1&1\\0&0&1&|&2&3&4\end{bmatrix}$
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