College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.4 - Page 639: 33

Answer

$\left\{\begin{array}{l} 4x-7y=-3\\ 2x-3y=1 \end{array}\right.$

Work Step by Step

The product on the LHS is between a 2$\times\underline{2}$ and a $\underline{2}\times$1 matrix, resulting in a 2$\times$1 matrix: $\left[\begin{array}{l} 4x-7y\\ 2x-3y \end{array}\right]$ Equating matrices, we have the system $\left\{\begin{array}{l} 4x-7y=-3\\ 2x-3y=1 \end{array}\right.$
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