College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.6 - Page 298: 82

Answer

$g(x) = 4x + 5$ $f(x) = \frac{1}{x}$

Work Step by Step

$h(x) = (f$o$g)(x)$ $= f(g(x))$ $= f(4x+5)$ $= \frac{1}{4x+5}$ $g(x) = 4x + 5$ $f(x) = \frac{1}{x}$
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